I have a list of tuples that look something like this:
(“Person 1”,10)
(“Person 2”,8)
(“Person 3”,12)
(“Person 4”,20)
What I want produced, is the list sorted in ascending order, by the second value of the tuple. So L[0] should be (“Person 2”, 8) after sorting.
How can I do this? Using Python 3.2.2 If that helps.
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Does python have immutable lists?
Suppose I wish to have the functionality of an ordered collection of elements, but which I want to guarantee will not change, how can this be implemented? Lists are ordered but they can be mutated.
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I’m testing the tuple structure, and I found it’s strange when I use the == operator like:
>>> (1,) == 1,
Out: (False,)
When I assign these two expressions to a variable, the result is true:
>>> a = (1,)
>>> b = 1,
>>> a==b
Out: True
This questions is different from Python tuple trailing comma syntax rule in my view. I ask the group of expressi….
In Python (I checked only with Python 3.6 but I believe it should hold for many of the previous versions as well):
(0, 0) == 0, 0 # results in a two element tuple: (False, 0)
0, 0 == (0, 0) # results in a two element tuple: (0, False)
(0, 0) == (0, 0) # results in a boolean True
But:
a = 0, 0
b = (0, 0)
a == b # results in a boolean True
Why….
A tuple takes less memory space in Python:
>>> a = (1,2,3)
>>> a.__sizeof__()
48
whereas lists takes more memory space:
>>> b = [1,2,3]
>>> b.__sizeof__()
64
What happens internally on the Python memory management?
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This question already has answers here:
Finding max value in the second column of a nested list?
(5 answers)
Closed 8 months ago.
I have a list with ~10^6 tuples in it like this:
[(101, 153), (255, 827), (361, 961), …]
^….
I would like do something like that.
list_of_urls = [‘http://www.google.fr/’, ‘http://www.google.fr/’,
‘http://www.google.cn/’, ‘http://www.google.com/’,
‘http://www.google.fr/’, ‘http://www.google.fr/’,
‘http://www.google.fr/’, ‘http://www.google.com/’,
‘http://www.google.fr/’, ‘….
I’m trying to obtain the n-th elements from a list of tuples.
I have something like:
elements = [(1,1,1),(2,3,7),(3,5,10)]
I wish to extract only the second elements of each tuple into a list:
seconds = [1, 3, 5]
I know that it could be done with a for loop but I wanted to know if there’s another way since I have thousands of tuples.
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Suppose I have a list of tuples and I want to convert to multiple lists.
For example, the list of tuples is
[(1,2),(3,4),(5,6),]
Is there any built-in function in Python that convert it to:
[1,3,5],[2,4,6]
This can be a simple program. But I am just curious about the existence of such built-in function in Python.
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In the case of a single element tuple, the trailing comma is required.
a = (‘foo’,)
What about a tuple with multiple elements? It seems that whether the trailing comma exists or not, they are both valid. Is this correct? Having a trailing comma is easier for editing in my opinion. Is that a bad coding style?
a = (‘foo1’, ‘foo2’)
b = (‘foo1’, ‘foo….