What I do in the command line:
cat file1 file2 file3 > myfile
What I want to do with python:
import subprocess, shlex
my_cmd = ‘cat file1 file2 file3 > myfile’
args = shlex.split(my_cmd)
subprocess.call(args) # spits the output in the window i call my python program
….
Can someone explain why the result I want, “hi”, is preceded with a letter ‘b’ and followed with a newline?
I am using Python 3.3
>>> import subprocess
>>> print(subprocess.Popen(“echo hi”, shell=True,
stdout=subprocess.PIPE).communicate()[0])
b’hi\n’
This extra ‘b’ does not appear if I run it with python 2.7
….
subprocess.call([“/home/myuser/run.sh”, “/tmp/ad_xml”, “/tmp/video_xml”])
RIght now I have a script that I run. When I run it and it hits this line, it starts printing stuff because run.sh has prints in it.
How do I pipe this to a text file also? (And also print, if possible)
….
This question already has answers here:
Why does passing variables to subprocess.Popen not work despite passing a list of arguments?
(5 answers)
Closed last year.
Since os.popen is being replaced by subprocess.popen, I was w….
I want to execute a script inside a subdirectory/superdirectory (I need to be inside this sub/super-directory first). I can’t get subprocess to enter my subdirectory:
tducin@localhost:~/Projekty/tests/ve$ python
Python 2.7.4 (default, Sep 26 2013, 03:20:26)
[GCC 4.7.3] on linux2
Type “help”, “copyright”, “credits” or “license” for more informatio….
From the examples in docs on subprocess.run() it seems like there shouldn’t be any output from
subprocess.run([“ls”, “-l”]) # doesn’t capture output
However, when I try it in a python shell the listing gets printed. I wonder if this is the default behaviour and how to suppress the output of run().
….
I am trying to write a wrapper script for a command line program (svnadmin verify) that will display a nice progress indicator for the operation. This requires me to be able to see each line of output from the wrapped program as soon as it is output.
I figured that I’d just execute the program using subprocess.Popen, use stdout=PIPE, then read ea….
I am trying to run a program to make some system calls inside Python code using subprocess.call() which throws the following error:
Traceback (most recent call last):
File “
File “/usr/lib/python2.7/subprocess.py”, line 493, in call
return Popen(*popenargs, **kwargs).wait()
File “/usr/lib/pyth….
What is the difference between subprocess.Popen() and os.system()?
….
I want to call an external program from Python. I have used both Popen() and call() to do that.
What’s the difference between the two?
My specific goal is to run the following command from Python. I am not sure how redirects work.
./my_script.sh > output
I read the documentation and it says that call() is a convenience function or a shortcut fun….