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Is it possible to modify a variable in python that is in an outer (enclosing), but not global, scope?
(9 answers)
Closed 8 years ago.
In the 2nd case below, Python tries to look for a ….
I have a situation like so…
class Outer(object):
def some_method(self):
# do something
class Inner(object):
def __init__(self):
self.Outer.some_method() # <-- this is the line in question
How can I access the Outer class's method from the Inner class?
....
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UnboundLocalError with nested function scopes [duplicate]
(3 answers)
Closed 4 years ago.
I’ve read almost all the other questions about the topic, but my code still doesn’t work.
I th….
This question already has answers here:
Using global variables in a function
(24 answers)
UnboundLocalError on local variable when reassigned after first use
(13 answers)
….
How do you access other class variables from a list comprehension within the class definition? The following works in Python 2 but fails in Python 3:
class Foo:
x = 5
y = [x for i in range(1)]
Python 3.2 gives the error:
NameError: global name ‘x’ is not defined
Trying Foo.x doesn’t work either. Any ideas on how to do this in Python 3?….
I’m not asking about Python’s scoping rules; I understand generally how scoping works in Python for loops. My question is why the design decisions were made in this way. For example (no pun intended):
for foo in xrange(10):
bar = 2
print(foo, bar)
The above will print (9,2).
This strikes me as weird: ‘foo’ is really just controlling the loop….
The following code works as expected in both Python 2.5 and 3.0:
a, b, c = (1, 2, 3)
print(a, b, c)
def test():
print(a)
print(b)
print(c) # (A)
#c+=1 # (B)
test()
However, when I uncomment line (B), I get an UnboundLocalError: ‘c’ not assigned at line (A). The values of a and b are printed correctly. This has me comple….
This question already has answers here:
Using global variables in a function
(24 answers)
Closed 3 years ago.
Is there a way to set up a global variable inside of a module? When I tried to do it the most obvious way as appea….
This question already has answers here:
UnboundLocalError on local variable when reassigned after first use
(13 answers)
Using global variables in a function
(24 answers)
….
I’m new to Python, so this is probably a simple scoping question. The following code in a Python file (module) is confusing me slightly:
if __name__ == ‘__main__’:
x = 1
print x
In other languages I’ve worked in, this code would throw an exception, as the x variable is local to the if statement and should not exist outside of it. But this co….