In Python, is there a function to check if a given file/directory is a symlink? For example, for the below files, my wrapper function should return True.
# ls -l
total 0
lrwxrwxrwx 1 root root 8 2012-06-16 18:58 dir -> ../temp/
lrwxrwxrwx 1 root root 6 2012-06-16 18:55 link -> ../log
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Ok…I dont know where module x is, but I know that I need to get the path to the directory two levels up.
So, is there a more elegant way to do:
import os
two_up = os.path.dirname(os.path.dirname(__file__))
Solutions for both Python 2 and 3 are welcome!
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I am trying to understand what is the motivation behind using Python’s library functions for executing OS-specific tasks such as creating files/directories, changing file attributes, etc. instead of just executing those commands via os.system() or subprocess.call()?
For example, why would I want to use os.chmod instead of doing os.system(“chmod…….
When multiple directories need to be concatenated, as in an executable search path, there is an os-dependent separator character. For Windows it’s ‘;’, for Linux it’s ‘:’. Is there a way in Python to get which character to split on?
In the discussions to this question How do I find out my python path using python? , it is suggested that os.sep w….
I want to check the operating system (on the computer where the script runs).
I know I can use os.system(‘uname -o’) in Linux, but it gives me a message in the console, and I want to write to a variable.
It will be okay if the script can tell if it is Mac, Windows or Linux. How can I check it?
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What do I need to look at to see whether I’m on Windows or Unix, etc?
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How do I check if the directory that a file is going to be written to exists, and if it does not, create the directory using Python?