This question already has answers here:
Accessing the index in ‘for’ loops
(26 answers)
Closed 8 years ago.
It is very common for me to loop through a python list to get both the contents and their indexes. What I usually do….
My attempt to programmatically create a dictionary of lists is failing to allow me to individually address dictionary keys. Whenever I create the dictionary of lists and try to append to one key, all of them are updated. Here’s a very simple test case:
data = {}
data = data.fromkeys(range(2),[])
data[1].append(‘hello’)
print data
Actual result: {….
I have a list of dictionaries, looking some thing like this:
list = [{‘id’: 123, ‘data’: ‘qwerty’, ‘indices’: [1,10]}, {‘id’: 345, ‘data’: ‘mnbvc’, ‘indices’: [2,11]}]
and so on. There may be more documents in the list. I need to convert these to one JSON document, that can be returned via bottle, and I cannot understand how to do this. Please he….
I was refactoring some old code of mine and came across of this:
alist.sort(cmp_items)
def cmp_items(a, b):
if a.foo > b.foo:
return 1
elif a.foo == b.foo:
return 0
else:
return -1
The code works (and I wrote it some 3 years ago!) but I cannot find this thing documented anywhere in the Python docs and everybod….
This question already has answers here:
How do I split a list into equally-sized chunks?
(72 answers)
Closed 5 months ago.
The community reviewed whether to reopen this question 5 months ago and left it closed:
Original close ….
my_list1 = [30,34,56]
my_list2 = [29,500,43]
How to I check if all values in list are >= 30? my_list1 should work and my_list2 should not.
The only thing I could think of doing was:
boolean = 0
def func(ls):
for k in ls:
if k >= 30:
boolean = boolean + 1
else:
boolean = 0
if boolean > 0:
pri….
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Check if multiple strings exist in another string
I can’t seem to find an equivalent of code that functions like this anywhere for Python:
Basically, I’d like to check a string for substrings contained in a….
This question already has answers here:
How can I iterate over overlapping (current, next) pairs of values from a list?
(12 answers)
Closed 2 years ago.
Given a list
l = [1, 7, 3, 5]
I want to iterate over all pairs of cons….
How to return False if all elements are in a list are False?
The given list is:
data = [False, False, False]
….
I want to change back and forth between a dictionary of (equal-length) lists:
DL = {‘a’: [0, 1], ‘b’: [2, 3]}
and a list of dictionaries:
LD = [{‘a’: 0, ‘b’: 2}, {‘a’: 1, ‘b’: 3}]
….