Fix Python – How to get folder name, in which given file resides, from pathlib.path?
Is there something similar to os.path.dirname(path), but in pathlib?
….
Is there something similar to os.path.dirname(path), but in pathlib?
….
At times, I’ve seen .pickle, .pck, .pcl, and .db for files that contain Python pickles, but I am unsure what is the most common or best practice. I know that the latter three extensions are also used for other things.
The related question is: What MIME type is preferred for sending pickles between systems using a REST API?
….
Is there a built-in function in Python that would replace (or remove, whatever) the extension of a filename (if it has one)?
Example:
print replace_extension(‘/home/user/somefile.txt’, ‘.jpg’)
In my example: /home/user/somefile.txt would become /home/user/somefile.jpg
I don’t know if it matters, but I need this for a SCons module I’m writing. (So….
I need to pass a file path name to a module. How do I build the file path from a directory name, base filename, and a file format string?
The directory may or may not exist at the time of call.
For example:
dir_name=’/home/me/dev/my_reports’
base_filename=’daily_report’
format = ‘pdf’
I need to create a string ‘/home/me/dev/my_reports/daily_repo….