I have a class where I want to override the __eq__ method. It seems to make sense that I should override the __ne__ method as well. Should I implement __ne__ as the negation of __eq__ as such or is it a bad idea?
class A:
def __init__(self, state):
self.state = state
def __eq__(self, other):
return self.state == other.sta….
Since Python does not provide left/right versions of its comparison operators, how does it decide which function to call?
class A(object):
def __eq__(self, other):
print “A __eq__ called”
return self.value == other
class B(object):
def __eq__(self, other):
print “B __eq__ called”
return self.value == other
….
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The following snippet is annotated with the output (as seen on ideone.com):
print “100” < "2" # True
print "5" > “9” # False
print “100” < 2 # False
print 100 < "2" # True
print 5 > “9” # False
print “5” > 9 # True
print [] > float(‘inf’) # True
print () > [] # True
Can someone explain why t….
a = [1, 2, 3, 1, 2, 3]
b = [3, 2, 1, 3, 2, 1]
a & b should be considered equal, because they have exactly the same elements, only in different order.
The thing is, my actual lists will consist of objects (my class instances), not integers.
….
I have been reading the Core Python programming book, and the author shows an example like:
(4, 5) < (3, 5) # Equals false
So, I'm wondering, how/why does it equal false? How does python compare these two tuples?
Btw, it's not explained in the book.
....
My editor warns me when I compare my_var == None, but no warning when I use my_var is None.
I did a test in the Python shell and determined both are valid syntax, but my editor seems to be saying that my_var is None is preferred.
Is this the case, and if so, why?
….
I am trying to compare the current date and time with dates and times specified in models using comparison operators:
if challenge.datetime_start <= datetime.now() <= challenge.datetime_end:
The script errors out with:
TypeError: can't compare offset-naive and offset-aware datetimes
The models look like this:
class Fundraising_Challenge(models.....
I have two dictionaries, but for simplification, I will take these two:
>>> x = dict(a=1, b=2)
>>> y = dict(a=2, b=2)
Now, I want to compare whether each key, value pair in x has the same corresponding value in y. So I wrote this:
>>> for x_values, y_values in zip(x.iteritems(), y.iteritems()):
if x_values == y_values:
print ‘….
This question already has answers here:
How to efficiently compare two unordered lists (not sets)?
(12 answers)
Closed 5 years ago.
I’m looking for an easy (and quick) way to determine if two unordered lists contain the same….