Asked By – C.B.
I am struggling to find a more clean way of returning a boolean value if my set is empty at the end of my function
I take the intersection of two sets, and want to return
False based on if the resulting set is empty.
def myfunc(a,b): c = a.intersection(b) #...return boolean here
My initial thought was to do
return c is not None
However, in my interpreter I can easily see that statement will return true if
c = set()
>>> c = set() >>> c is not None True
I’ve also tried all of the following:
>>> c == None False >>> c == False False >>> c is None False
Now I’ve read from the documentation that I can only use
not with empty sets to deduce a boolean value. So far, the only thing I can come up with is returning not not c
>>> not not c False >>> not c True
I have a feeling there is a much more pythonic way to do this, by I am struggling to find it. I don’t want to return the actual set to an if statement because I don’t need the values, I just want to know if they intersect.
Now we will see solution for issue: Returning boolean if set is empty
def myfunc(a,b): c = a.intersection(b) return bool(c)
bool() will do something similar to
not not, but more ideomatic and clear.