Question
Asked By – flonk
Given a list
l = [1, 7, 3, 5]
I want to iterate over all pairs of consecutive list items (1,7), (7,3), (3,5)
, i.e.
for i in xrange(len(l) - 1):
x = l[i]
y = l[i + 1]
# do something
I would like to do this in a more compact way, like
for x, y in someiterator(l): ...
Is there a way to do do this using builtin Python iterators? I’m sure the itertools
module should have a solution, but I just can’t figure it out.
Now we will see solution for issue: Iterate over all pairs of consecutive items in a list [duplicate]
Answer
Just use zip
>>> l = [1, 7, 3, 5]
>>> for first, second in zip(l, l[1:]):
... print first, second
...
1 7
7 3
3 5
If you use Python 2 (not suggested) you might consider using the izip
function in itertools
for very long lists where you don’t want to create a new list.
import itertools
for first, second in itertools.izip(l, l[1:]):
...
This question is answered By – sberry
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