Question
Asked By – talnicolas
My python script executes an os.listdir(path)
where the path is a queue containing archives that I need to treat one by one.
The problem is that I’m getting the list in an array and then I just do a simple array.pop(0)
. It was working fine until I put the project in subversion. Now I get the .svn
folder in my array and of course it makes my application crash.
So here is my question: is there a function that ignores hidden files when executing an os.listdir()
and if not what would be the best way?
Now we will see solution for issue: How to ignore hidden files using os.listdir()?
Answer
You can write one yourself:
import os
def listdir_nohidden(path):
for f in os.listdir(path):
if not f.startswith('.'):
yield f
Or you can use a glob:
import glob
import os
def listdir_nohidden(path):
return glob.glob(os.path.join(path, '*'))
Either of these will ignore all filenames beginning with '.'
.
This question is answered By – Adam Rosenfield
This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0