Asked By – lxyu
I have to convert a timezone-aware string like
"2012-11-01T04:16:13-04:00" to a Python
I saw the
dateutil module which has a parse function, but I don’t really want to use it as it adds a dependency.
So how can I do it? I have tried something like the following, but with no luck.
Now we will see solution for issue: How to convert a timezone aware string to datetime in Python without dateutil?
As of Python 3.7,
datetime.datetime.fromisoformat() can handle your format:
>>> import datetime >>> datetime.datetime.fromisoformat('2012-11-01T04:16:13-04:00') datetime.datetime(2012, 11, 1, 4, 16, 13, tzinfo=datetime.timezone(datetime.timedelta(days=-1, seconds=72000)))
In older Python versions you can’t, not without a whole lot of painstaking manual timezone defining.
Python does not include a timezone database, because it would be outdated too quickly. Instead, Python relies on external libraries, which can have a far faster release cycle, to provide properly configured timezones for you.
As a side-effect, this means that timezone parsing also needs to be an external library. If
dateutil is too heavy-weight for you, use
iso8601 instead, it’ll parse your specific format just fine:
>>> import iso8601 >>> iso8601.parse_date('2012-11-01T04:16:13-04:00') datetime.datetime(2012, 11, 1, 4, 16, 13, tzinfo=<FixedOffset '-04:00'>)
iso8601 is a whopping 4KB small. Compare that tot
As of Python 3.2 Python can handle simple offset-based timezones, and
%z will parse
+hhmm timezone offsets in a timestamp. That means that for a ISO 8601 timestamp you’d have to remove the
: in the timezone:
>>> from datetime import datetime >>> iso_ts = '2012-11-01T04:16:13-04:00' >>> datetime.strptime(''.join(iso_ts.rsplit(':', 1)), '%Y-%m-%dT%H:%M:%S%z') datetime.datetime(2012, 11, 1, 4, 16, 13, tzinfo=datetime.timezone(datetime.timedelta(-1, 72000)))
The lack of proper ISO 8601 parsing is being tracked in Python issue 15873.