# Fix Python – Counting the number of non-NaN elements in a numpy ndarray in Python

## Question

I need to calculate the number of non-NaN elements in a numpy ndarray matrix. How would one efficiently do this in Python? Here is my simple code for achieving this:

``````import numpy as np

def numberOfNonNans(data):
count = 0
for i in data:
if not np.isnan(i):
count += 1
return count
``````

Is there a built-in function for this in numpy? Efficiency is important because I’m doing Big Data analysis.

Thnx for any help!

Now we will see solution for issue: Counting the number of non-NaN elements in a numpy ndarray in Python

``````np.count_nonzero(~np.isnan(data))
``````

`~` inverts the boolean matrix returned from `np.isnan`.

`np.count_nonzero` counts values that is not 0\false. `.sum` should give the same result. But maybe more clearly to use `count_nonzero`

Testing speed:

``````In : data = np.random.random((10000,10000))

In : data[[np.random.random_integers(0,10000, 100)],:][:, [np.random.random_integers(0,99, 100)]] = np.nan

In : %timeit data.size - np.count_nonzero(np.isnan(data))
1 loops, best of 3: 309 ms per loop

In : %timeit np.count_nonzero(~np.isnan(data))
1 loops, best of 3: 345 ms per loop

In : %timeit data.size - np.isnan(data).sum()
1 loops, best of 3: 339 ms per loop
``````

`data.size - np.count_nonzero(np.isnan(data))` seems to barely be the fastest here. other data might give different relative speed results.

This question is answered By – M4rtini