Fix Python – Conditional with statement in Python


Asked By – norman

Is there a way to begin a block of code with a with statement, but conditionally?

Something like:

if needs_with():
    with get_stuff() as gs:

# do nearly the same large block of stuff,
# involving gs or not, depending on needs_with()

To clarify, one scenario would have a block encased in the with statement, while another possibility would be the same block, but not encased (i.e., as if it wasn’t indented)

Initial experiments of course give indentation errors..

Now we will see solution for issue: Conditional with statement in Python


If you want to avoid duplicating code and are using a version of Python prior to 3.7 (when contextlib.nullcontext was introduced) or even 3.3 (when contextlib.ExitStack was introduced), you could do something like:

class dummy_context_mgr():
    def __enter__(self):
        return None
    def __exit__(self, exc_type, exc_value, traceback):
        return False


import contextlib

def dummy_context_mgr():
    yield None

and then use it as:

with get_stuff() if needs_with() else dummy_context_mgr() as gs:
   # do stuff involving gs or not

You alternatively could make get_stuff() return different things based on needs_with().

(See Mike’s answer or Daniel’s answer for what you can do in later versions.)

This question is answered By – jamesdlin

This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0