Fix Python – What does the caret (^) operator do?

Question

Asked By – Fry

I ran across the caret operator in python today and trying it out, I got the following output:

>>> 8^3
11
>>> 8^4
12
>>> 8^1
9
>>> 8^0
8
>>> 7^1
6
>>> 7^2
5
>>> 7^7
0
>>> 7^8
15
>>> 9^1
8
>>> 16^1
17
>>> 15^1
14
>>>

It seems to be based on 8, so I’m guessing some sort of byte operation? I can’t seem to find much about this searching sites other than it behaves oddly for floats, does anybody have a link to what this operator does or can you explain it here?

Now we will see solution for issue: What does the caret (^) operator do?


Answer

It’s a bitwise XOR (exclusive OR).

It evaluates to True if and only if its arguments differ (one is True, the other is False).

To demonstrate:

>>> 0^0
0
>>> 1^1
0
>>> 1^0
1
>>> 0^1
1

To explain one of your own examples:

>>> 8^3
11

Think about it this way:

1000  # 8 (binary)
0011  # 3 (binary)
----  # APPLY XOR ('vertically')
1011  # result = 11 (binary)

This question is answered By – ChristopheD

This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0