Fix Python – What does preceding a string literal with “r” mean? [duplicate]


Asked By – Nikki Erwin Ramirez

I first saw it used in building regular expressions across multiple lines as a method argument to re.compile(), so I assumed that r stands for RegEx.

For example:

regex = re.compile(
    r'[A-Z]$', re.IGNORECASE

So what does r mean in this case? Why do we need it?

Now we will see solution for issue: What does preceding a string literal with “r” mean? [duplicate]


The r means that the string is to be treated as a raw string, which means all escape codes will be ignored.

For an example:

'\n' will be treated as a newline character, while r'\n' will be treated as the characters \ followed by n.

When an 'r' or 'R' prefix is present,
a character following a backslash is
included in the string without change,
and all backslashes are left in the
string. For example, the string
literal r"\n" consists of two
characters: a backslash and a
lowercase 'n'. String quotes can be
escaped with a backslash, but the
backslash remains in the string; for
example, r"\"" is a valid string
literal consisting of two characters:
a backslash and a double quote; r"\"
is not a valid string literal (even a
raw string cannot end in an odd number
of backslashes). Specifically, a raw
string cannot end in a single
backslash (since the backslash would
escape the following quote character).
Note also that a single backslash
followed by a newline is interpreted
as those two characters as part of the
string, not as a line continuation.

Source: Python string literals

This question is answered By – Sebastian Paaske Tørholm

This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0