Question
Asked By – Josh
I was trying to scrape a website for practice, but I kept on getting the HTTP Error 403 (does it think I’m a bot)?
Here is my code:
#import requests
import urllib.request
from bs4 import BeautifulSoup
#from urllib import urlopen
import re
webpage = urllib.request.urlopen('http://www.cmegroup.com/trading/products/#sortField=oi&sortAsc=false&venues=3&page=1&cleared=1&group=1').read
findrows = re.compile('<tr class="- banding(?:On|Off)>(.*?)</tr>')
findlink = re.compile('<a href =">(.*)</a>')
row_array = re.findall(findrows, webpage)
links = re.finall(findlink, webpate)
print(len(row_array))
iterator = []
The error I get is:
File "C:\Python33\lib\urllib\request.py", line 160, in urlopen
return opener.open(url, data, timeout)
File "C:\Python33\lib\urllib\request.py", line 479, in open
response = meth(req, response)
File "C:\Python33\lib\urllib\request.py", line 591, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python33\lib\urllib\request.py", line 517, in error
return self._call_chain(*args)
File "C:\Python33\lib\urllib\request.py", line 451, in _call_chain
result = func(*args)
File "C:\Python33\lib\urllib\request.py", line 599, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 403: Forbidden
Now we will see solution for issue: Problem HTTP error 403 in Python 3 Web Scraping
Answer
This is probably because of mod_security
or some similar server security feature which blocks known spider/bot user agents (urllib
uses something like python urllib/3.3.0
, it’s easily detected). Try setting a known browser user agent with:
from urllib.request import Request, urlopen
req = Request(
url='http://www.cmegroup.com/trading/products/#sortField=oi&sortAsc=false&venues=3&page=1&cleared=1&group=1',
headers={'User-Agent': 'Mozilla/5.0'}
)
webpage = urlopen(req).read()
This works for me.
By the way, in your code you are missing the ()
after .read
in the urlopen
line, but I think that it’s a typo.
TIP: since this is exercise, choose a different, non restrictive site. Maybe they are blocking urllib
for some reason…
This question is answered By – Stefano Sanfilippo
This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0