Fix Python – One-liner to check whether an iterator yields at least one element?

Currently I’m doing this:

try:
    something = iterator.next()
    # ...
except StopIteration:
    # ...

But I would like an expression that I can place inside a simple if statement.
Is there anything built-in which would make this code look less clumsy?

any() returns False if an iterable is empty, but it will potentially iterate over all the items if it’s not.
I only need it to check the first item.

Someone asks what I’m trying to do.
I have written a function which executes an SQL query and yields its results.
Sometimes when I call this function I just want to know if the query returned anything and make a decision based on that.