Fix Python – Numpy Resize/Rescale Image


Asked By – Brian Hamill

I would like to take an image and change the scale of the image, while it is a numpy array.

For example I have this image of a coca-cola bottle:

Which translates to a numpy array of shape (528, 203, 3) and I want to resize that to say the size of this second image:

Which has a shape of (140, 54, 3).

How do I change the size of the image to a certain shape while still maintaining the original image? Other answers suggest stripping every other or third row out, but what I want to do is basically shrink the image how you would via an image editor but in python code. Are there any libraries to do this in numpy/SciPy?

Now we will see solution for issue: Numpy Resize/Rescale Image


Yeah, you can install opencv (this is a library used for image processing, and computer vision), and use the cv2.resize function. And for instance use:

import cv2
import numpy as np

img = cv2.imread('your_image.jpg')
res = cv2.resize(img, dsize=(54, 140), interpolation=cv2.INTER_CUBIC)

Here img is thus a numpy array containing the original image, whereas res is a numpy array containing the resized image. An important aspect is the interpolation parameter: there are several ways how to resize an image. Especially since you scale down the image, and the size of the original image is not a multiple of the size of the resized image. Possible interpolation schemas are:

  • INTER_NEAREST – a nearest-neighbor interpolation
  • INTER_LINEAR – a bilinear interpolation (used by default)
  • INTER_AREA – resampling using pixel area relation. It may be a preferred method for image decimation, as it gives moire’-free
    results. But when the image is zoomed, it is similar to the
    INTER_NEAREST method.
  • INTER_CUBIC – a bicubic interpolation over 4×4 pixel neighborhood
  • INTER_LANCZOS4 – a Lanczos interpolation over 8×8 pixel neighborhood

Like with most options, there is no “best” option in the sense that for every resize schema, there are scenarios where one strategy can be preferred over another.

This question is answered By – Willem Van Onsem

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