Question
Asked By – zjm1126
this code is get the templates/blog1/page.html in b.py:
path = os.path.join(os.path.dirname(__file__), os.path.join('templates', 'blog1/page.html'))
but i want to get the parent dir location:
aParent
|--a
| |---b.py
| |---templates
| |--------blog1
| |-------page.html
|--templates
|--------blog1
|-------page.html
and how to get the aParent location
thanks
updated:
this is right:
dirname=os.path.dirname
path = os.path.join(dirname(dirname(__file__)), os.path.join('templates', 'blog1/page.html'))
or
path = os.path.abspath(os.path.join(os.path.dirname(__file__),".."))
Now we will see solution for issue: How to get the parent dir location
Answer
You can apply dirname repeatedly to climb higher: dirname(dirname(file))
. This can only go as far as the root package, however. If this is a problem, use os.path.abspath
: dirname(dirname(abspath(file)))
.
This question is answered By – Marcelo Cantos
This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0