Asked By – TIMEX
subprocess.call(["/home/myuser/run.sh", "/tmp/ad_xml", "/tmp/video_xml"])
RIght now I have a script that I run. When I run it and it hits this line, it starts printing stuff because run.sh has prints in it.
How do I pipe this to a text file also? (And also print, if possible)
Now we will see solution for issue: How do I pipe a subprocess call to a text file?
If you want to write the output to a file you can use the stdout-argument of
It takes either
None(the default, stdout is inherited from the parent (your script))
subprocess.PIPE(allows you to pipe from one command/process to another)
- a file object or a file descriptor (what you want, to have the output written to a file)
You need to open a file with something like
open and pass the object or file descriptor integer to
f = open("blah.txt", "w") subprocess.call(["/home/myuser/run.sh", "/tmp/ad_xml", "/tmp/video_xml"], stdout=f)
I’m guessing any valid file-like object would work, like a socket (gasp :)), but I’ve never tried.
As marcog mentions in the comments you might want to redirect stderr as well, you can redirect this to the same location as stdout with
stderr=subprocess.STDOUT. Any of the above mentioned values works as well, you can redirect to different places.
This question is answered By – Skurmedel
This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0