Fix Python – How can I check if an ip is in a network in Python?

Question

Asked By – Staale

Given an ip address (say 192.168.0.1), how do I check if it’s in a network (say 192.168.0.0/24) in Python?

Are there general tools in Python for ip address manipulation? Stuff like host lookups, ip adddress to int, network address with netmask to int and so on? Hopefully in the standard Python library for 2.5.

Now we will see solution for issue: How can I check if an ip is in a network in Python?


Answer

This article shows you can do it with socket and struct modules without too much extra effort. I added a little to the article as follows:

import socket,struct

def makeMask(n):
    "return a mask of n bits as a long integer"
    return (2L<<n-1) - 1

def dottedQuadToNum(ip):
    "convert decimal dotted quad string to long integer"
    return struct.unpack('L',socket.inet_aton(ip))[0]

def networkMask(ip,bits):
    "Convert a network address to a long integer" 
    return dottedQuadToNum(ip) & makeMask(bits)

def addressInNetwork(ip,net):
   "Is an address in a network"
   return ip & net == net

address = dottedQuadToNum("192.168.1.1")
networka = networkMask("10.0.0.0",24)
networkb = networkMask("192.168.0.0",24)
print (address,networka,networkb)
print addressInNetwork(address,networka)
print addressInNetwork(address,networkb)

This outputs:

False
True

If you just want a single function that takes strings it would look like this:

import socket,struct

def addressInNetwork(ip,net):
   "Is an address in a network"
   ipaddr = struct.unpack('L',socket.inet_aton(ip))[0]
   netaddr,bits = net.split('/')
   netmask = struct.unpack('L',socket.inet_aton(netaddr))[0] & ((2L<<int(bits)-1) - 1)
   return ipaddr & netmask == netmask

This question is answered By – David Webb

This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0