Question
Asked By – Staale
Given an ip address (say 192.168.0.1), how do I check if it’s in a network (say 192.168.0.0/24) in Python?
Are there general tools in Python for ip address manipulation? Stuff like host lookups, ip adddress to int, network address with netmask to int and so on? Hopefully in the standard Python library for 2.5.
Now we will see solution for issue: How can I check if an ip is in a network in Python?
Answer
This article shows you can do it with socket
and struct
modules without too much extra effort. I added a little to the article as follows:
import socket,struct
def makeMask(n):
"return a mask of n bits as a long integer"
return (2L<<n-1) - 1
def dottedQuadToNum(ip):
"convert decimal dotted quad string to long integer"
return struct.unpack('L',socket.inet_aton(ip))[0]
def networkMask(ip,bits):
"Convert a network address to a long integer"
return dottedQuadToNum(ip) & makeMask(bits)
def addressInNetwork(ip,net):
"Is an address in a network"
return ip & net == net
address = dottedQuadToNum("192.168.1.1")
networka = networkMask("10.0.0.0",24)
networkb = networkMask("192.168.0.0",24)
print (address,networka,networkb)
print addressInNetwork(address,networka)
print addressInNetwork(address,networkb)
This outputs:
False
True
If you just want a single function that takes strings it would look like this:
import socket,struct
def addressInNetwork(ip,net):
"Is an address in a network"
ipaddr = struct.unpack('L',socket.inet_aton(ip))[0]
netaddr,bits = net.split('/')
netmask = struct.unpack('L',socket.inet_aton(netaddr))[0] & ((2L<<int(bits)-1) - 1)
return ipaddr & netmask == netmask
This question is answered By – David Webb
This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0