Fix Python – Getting the caller function name inside another function in Python? [duplicate]

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Question

Asked By – Joan Venge

If you have 2 functions like:

def A
def B

and A calls B, can you get who is calling B inside B, like:

def A () :
    B ()

def B () :
    this.caller.name

Now we will see solution for issue: Getting the caller function name inside another function in Python? [duplicate]

Answer

You can use the inspect module to get the info you want. Its stack method returns a list of frame records.

  • For Python 2 each frame record is a list. The third element in each record is the caller name. What you want is this:

    >>> import inspect
>>> def f():
...     print inspect.stack()[1][3]
...
>>> def g():
...     f()
...
>>> g()
g

  • For Python 3.5+, each frame record is a named tuple so you need to replace

    print inspect.stack()[1][3]

    with 

    print(inspect.stack()[1].function)

    on the above code.

This question is answered By – Ayman Hourieh

This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0