Fix Python – Download Returned Zip file from URL

Question

Asked By – user1229108

If I have a URL that, when submitted in a web browser, pops up a dialog box to save a zip file, how would I go about catching and downloading this zip file in Python?

Now we will see solution for issue: Download Returned Zip file from URL


Answer

Most people recommend using requests if it is available, and the requests documentation recommends this for downloading and saving raw data from a url:

import requests 

def download_url(url, save_path, chunk_size=128):
    r = requests.get(url, stream=True)
    with open(save_path, 'wb') as fd:
        for chunk in r.iter_content(chunk_size=chunk_size):
            fd.write(chunk)

Since the answer asks about downloading and saving the zip file, I haven’t gone into details regarding reading the zip file. See one of the many answers below for possibilities.

If for some reason you don’t have access to requests, you can use urllib.request instead. It may not be quite as robust as the above.

import urllib.request

def download_url(url, save_path):
    with urllib.request.urlopen(url) as dl_file:
        with open(save_path, 'wb') as out_file:
            out_file.write(dl_file.read())

Finally, if you are using Python 2 still, you can use urllib2.urlopen.

from contextlib import closing

def download_url(url, save_path):
    with closing(urllib2.urlopen(url)) as dl_file:
        with open(save_path, 'wb') as out_file:
            out_file.write(dl_file.read())

This question is answered By – senderle

This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0