Asked By – Paolo Bergantino
This was fixed in Django 1.9 with form_kwargs.
I have a Django Form that looks like this:
class ServiceForm(forms.Form): option = forms.ModelChoiceField(queryset=ServiceOption.objects.none()) rate = forms.DecimalField(widget=custom_widgets.SmallField()) units = forms.IntegerField(min_value=1, widget=custom_widgets.SmallField()) def __init__(self, *args, **kwargs): affiliate = kwargs.pop('affiliate') super(ServiceForm, self).__init__(*args, **kwargs) self.fields["option"].queryset = ServiceOption.objects.filter(affiliate=affiliate)
I call this form with something like this:
form = ServiceForm(affiliate=request.affiliate)
request.affiliate is the logged in user. This works as intended.
My problem is that I now want to turn this single form into a formset. What I can’t figure out is how I can pass the affiliate information to the individual forms when creating the formset. According to the docs to make a formset out of this I need to do something like this:
ServiceFormSet = forms.formsets.formset_factory(ServiceForm, extra=3)
And then I need to create it like this:
formset = ServiceFormSet()
Now how can I pass affiliate=request.affiliate to the individual forms this way?
Now we will see solution for issue: Django Passing Custom Form Parameters to Formset
from functools import partial, wraps from django.forms.formsets import formset_factory ServiceFormSet = formset_factory(wraps(ServiceForm)(partial(ServiceForm, affiliate=request.affiliate)), extra=3)
I think this is the cleanest approach, and doesn’t affect ServiceForm in any way (i.e. by making it difficult to subclass).