Fix Python – Copy file with pathlib in Python

Question

Asked By – guettli

I try to copy a file with pathlib

import pathlib
import shutil

my_file=pathlib.Path('/etc/hosts')
to_file=pathlib.Path('/tmp/foo')
shutil.copy(my_file, to_file)

I get this exception:

/home/foo_egs_d/bin/python /home/foo_egs_d/src/test-pathlib-copy.py
Traceback (most recent call last):
  File "/home/foo_egs_d/src/test-pathlib-copy.py", line 6, in <module>
    shutil.copy(my_file, to_file)
  File "/usr/lib/python2.7/shutil.py", line 117, in copy
    if os.path.isdir(dst):
  File "/home/foo_egs_d/lib/python2.7/genericpath.py", line 41, in isdir
    st = os.stat(s)
TypeError: coercing to Unicode: need string or buffer, PosixPath found

Process finished with exit code

… how to copy file with pathlib in Python 2.7?

Now we will see solution for issue: Copy file with pathlib in Python


Answer

To use shutil.copy:

import pathlib
import shutil

my_file = pathlib.Path('/etc/hosts')
to_file = pathlib.Path('/tmp/foo')

shutil.copy(str(my_file), str(to_file))  # For Python <= 3.7.
shutil.copy(my_file, to_file)  # For Python 3.8+.

The problem is pathlib.Path create a PosixPath object if you’re using Unix/Linux, WindowsPath if you’re using Microsoft Windows.

With older versions of Python, shutil.copy requires a string as its arguments. For them, use the str function here.

This question is answered By – Remi Guan

This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0