Asked By – Pete
I’m using the
datetime module, i.e.:
>>> import datetime >>> today = datetime.datetime.now() >>> print(today) 2009-03-06 13:24:58.857946
and I would like to compute the day of year that takes leap years into account. e.g. today (March 6, 2009) is the 65th day of 2009.
I see a two options:
number_of_days_in_month = [31, 28, ...]array, decide if it’s a leap year and manually sum up the days.
datetime.timedeltato make a guess & then binary search for the correct day of the year:
>>> import datetime >>> YEAR = 2009 >>> DAY_OF_YEAR = 62 >>> d = datetime.date(YEAR, 1, 1) + datetime.timedelta(DAY_OF_YEAR - 1)
These both feel pretty clunky & I have a gut feeling that there’s a more “Pythonic” way of calculating the day of the year. Any ideas/suggestions?
Now we will see solution for issue: Convert Year/Month/Day to Day of Year in Python