Fix Python – Convert Year/Month/Day to Day of Year in Python


Asked By – Pete

I’m using the datetime module, i.e.:

>>> import datetime
>>> today =
>>> print(today)
2009-03-06 13:24:58.857946

and I would like to compute the day of year that takes leap years into account. e.g. today (March 6, 2009) is the 65th day of 2009.

I see a two options:

  1. Create a number_of_days_in_month = [31, 28, ...] array, decide if it’s a leap year and manually sum up the days.

  2. Use datetime.timedelta to make a guess & then binary search for the correct day of the year:

    >>> import datetime
    >>> YEAR = 2009
    >>> DAY_OF_YEAR = 62
    >>> d =, 1, 1) + datetime.timedelta(DAY_OF_YEAR - 1)

These both feel pretty clunky & I have a gut feeling that there’s a more “Pythonic” way of calculating the day of the year. Any ideas/suggestions?

Now we will see solution for issue: Convert Year/Month/Day to Day of Year in Python


Use datetime.timetuple() to convert your datetime object to a time.struct_time object then get its tm_yday property:

from datetime import datetime
day_of_year =  # returns 1 for January 1st

This question is answered By – DzinX

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