Asked By – Jiew Meng
I want to check if my list of objects contain an object with a certain attribute value.
class Test: def __init__(self, name): self.name = name # in main() l =  l.append(Test("t1")) l.append(Test("t2")) l.append(Test("t2"))
I want a way of checking if list contains an object with name
"t1" for example. How can it be done? I found https://stackoverflow.com/a/598415/292291,
[x for x in myList if x.n == 30] # list of all matches any(x.n == 30 for x in myList) # if there is any matches [i for i,x in enumerate(myList) if x.n == 30] # indices of all matches def first(iterable, default=None): for item in iterable: return item return default first(x for x in myList if x.n == 30) # the first match, if any
I don’t want to go through the whole list every time, I just need to know if there’s 1 instance which matches. Will
any(...) or something else do that?
Now we will see solution for issue: Check if list of objects contain an object with a certain attribute value
As you can easily see from the documentation, the
any() function short-circuits an returns
True as soon as a match has been found.
any(x.name == "t2" for x in l)
This question is answered By – Sven Marnach
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