Fix Python – Call a function with argument list in python


Asked By – SurDin

I’m trying to call a function inside another function in python, but can’t find the right syntax. What I want to do is something like this:

def wrapper(func, args):

def func1(x):

def func2(x, y, z):
    return x+y+z

wrapper(func1, [x])
wrapper(func2, [x, y, z])

In this case first call will work, and second won’t.
What I want to modify is the wrapper function and not the called functions.

Now we will see solution for issue: Call a function with argument list in python


To expand a little on the other answers:

In the line:

def wrapper(func, *args):

The * next to args means “take the rest of the parameters given and put them in a list called args“.

In the line:


The * next to args here means “take this list called args and ‘unwrap’ it into the rest of the parameters.

So you can do the following:

def wrapper1(func, *args): # with star

def wrapper2(func, args): # without star

def func2(x, y, z):
    print x+y+z

wrapper1(func2, 1, 2, 3)
wrapper2(func2, [1, 2, 3])

In wrapper2, the list is passed explicitly, but in both wrappers args contains the list [1,2,3].

This question is answered By – itsadok

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