Fix Python – How to validate a url in Python? (Malformed or not)


Asked By – Yugal Jindle

I have url from the user and I have to reply with the fetched HTML.

How can I check for the URL to be malformed or not?

For example :

url = 'google' # Malformed
url = '' # Malformed
url = '' # Valid
url = 'http://google' # Malformed

Now we will see solution for issue: How to validate a url in Python? (Malformed or not)


django url validation regex (source):

import re
regex = re.compile(
        r'^(?:http|ftp)s?://' # http:// or https://
        r'(?:(?:[A-Z0-9](?:[A-Z0-9-]{0,61}[A-Z0-9])?\.)+(?:[A-Z]{2,6}\.?|[A-Z0-9-]{2,}\.?)|' #domain...
        r'localhost|' #localhost...
        r'\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})' # ...or ip
        r'(?::\d+)?' # optional port
        r'(?:/?|[/?]\S+)$', re.IGNORECASE)

print(re.match(regex, "") is not None) # True
print(re.match(regex, "") is not None)            # False

This question is answered By – cetver

This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0