Fix Python – Find the most frequent number in a NumPy array

Question

Asked By – JustInTime

Suppose I have the following NumPy array:

``````a = np.array([1,2,3,1,2,1,1,1,3,2,2,1])
``````

How can I find the most frequent number in this array?

Now we will see solution for issue: Find the most frequent number in a NumPy array

If your list contains all non-negative ints, you should take a look at numpy.bincounts:

http://docs.scipy.org/doc/numpy/reference/generated/numpy.bincount.html

and then probably use np.argmax:

``````a = np.array([1,2,3,1,2,1,1,1,3,2,2,1])
counts = np.bincount(a)
print(np.argmax(counts))
``````

For a more complicated list (that perhaps contains negative numbers or non-integer values), you can use `np.histogram` in a similar way. Alternatively, if you just want to work in python without using numpy, `collections.Counter` is a good way of handling this sort of data.

``````from collections import Counter
a = [1,2,3,1,2,1,1,1,3,2,2,1]
b = Counter(a)
print(b.most_common(1))
``````

This question is answered By – JoshAdel

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