## Question

Asked By – JustInTime

Suppose I have the following NumPy array:

```
a = np.array([1,2,3,1,2,1,1,1,3,2,2,1])
```

How can I find the most frequent number in this array?

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## Answer

If your list contains all non-negative ints, you should take a look at numpy.bincounts:

http://docs.scipy.org/doc/numpy/reference/generated/numpy.bincount.html

and then probably use np.argmax:

```
a = np.array([1,2,3,1,2,1,1,1,3,2,2,1])
counts = np.bincount(a)
print(np.argmax(counts))
```

For a more complicated list (that perhaps contains negative numbers or non-integer values), you can use `np.histogram`

in a similar way. Alternatively, if you just want to work in python without using numpy, `collections.Counter`

is a good way of handling this sort of data.

```
from collections import Counter
a = [1,2,3,1,2,1,1,1,3,2,2,1]
b = Counter(a)
print(b.most_common(1))
```

This question is answered By – JoshAdel

**This answer is collected from stackoverflow and reviewed by FixPython community admins, is licensed under cc by-sa 2.5 , cc by-sa 3.0 and cc by-sa 4.0 **