Asked By – RuiDC
Why is the below item failing? Why does it succeed with “latin-1” codec?
o = "a test of \xe9 char" #I want this to remain a string as this is what I am receiving v = o.decode("utf-8")
Which results in:
Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python27\lib\encodings\utf_8.py", line 16, in decode return codecs.utf_8_decode(input, errors, True) UnicodeDecodeError: 'utf8' codec can't decode byte 0xe9 in position 10: invalid continuation byte
Now we will see solution for issue: UnicodeDecodeError, invalid continuation byte
In binary, 0xE9 looks like
1110 1001. If you read about UTF-8 on Wikipedia, you’ll see that such a byte must be followed by two of the form
10xx xxxx. So, for example:
>>> b'\xe9\x80\x80'.decode('utf-8') u'\u9000'
But that’s just the mechanical cause of the exception. In this case, you have a string that is almost certainly encoded in latin 1. You can see how UTF-8 and latin 1 look different:
>>> u'\xe9'.encode('utf-8') b'\xc3\xa9' >>> u'\xe9'.encode('latin-1') b'\xe9'
(Note, I’m using a mix of Python 2 and 3 representation here. The input is valid in any version of Python, but your Python interpreter is unlikely to actually show both unicode and byte strings in this way.)