Fix Python – Iterating through a range of dates in Python


Asked By – ShawnMilo

I have the following code to do this, but how can I do it better? Right now I think it’s better than nested loops, but it starts to get Perl-one-linerish when you have a generator in a list comprehension.

day_count = (end_date - start_date).days + 1
for single_date in [d for d in (start_date + timedelta(n) for n in range(day_count)) if d <= end_date]:
    print strftime("%Y-%m-%d", single_date.timetuple())


  • I’m not actually using this to print. That’s just for demo purposes.
  • The start_date and end_date variables are objects because I don’t need the timestamps. (They’re going to be used to generate a report).

Sample Output

For a start date of 2009-05-30 and an end date of 2009-06-09:


Now we will see solution for issue: Iterating through a range of dates in Python


Why are there two nested iterations? For me it produces the same list of data with only one iteration:

for single_date in (start_date + timedelta(n) for n in range(day_count)):
    print ...

And no list gets stored, only one generator is iterated over. Also the “if” in the generator seems to be unnecessary.

After all, a linear sequence should only require one iterator, not two.

Update after discussion with John Machin:

Maybe the most elegant solution is using a generator function to completely hide/abstract the iteration over the range of dates:

from datetime import date, timedelta

def daterange(start_date, end_date):
    for n in range(int((end_date - start_date).days)):
        yield start_date + timedelta(n)

start_date = date(2013, 1, 1)
end_date = date(2015, 6, 2)
for single_date in daterange(start_date, end_date):

NB: For consistency with the built-in range() function this iteration stops before reaching the end_date. So for inclusive iteration use the next day, as you would with range().

This question is answered By – Ber

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